This tip on improving your SAT score was provided by Veritas Prep.
Euclidean and coordinate geometry are both subjects youâll want to be familiar with on the SAT in order to score well. A dozen or so questions always relate to geometry concepts. While trigonometry is not an official topic for the SAT, you do need to know how and when to apply the Pythagorean Theorem for certain problems. Donât worry though: You donât need to memorize the formula because a formula table is provided at the beginning of every single SAT math section.
We want to emphasize that the SAT wonât just be about plugging numbers into the formula and chugging out an answer; it will require you to use reasoning skills to determine when itâs appropriate and useful to apply the Pythagorean Theorem. In addition, there will be times when it wonât even be obvious that you can apply the formula in order to help you solve a problem. You will then need to look for âhidden trianglesâ in the problem to help you reach the solution. Once you know what to look for, youâll start seeing hidden right triangles everywhere and be able to use them to your advantage to solve difficult geometry SAT problems.
Letâs take a look at the following question that appeared on the Official SAT Practice Test from 2007-2008:
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What is the perimeter of the trapezoid above?
A) 52
B) 72
C) 75
D) 80
E) 87
Do you remember the formula for finding the perimeter of a trapezoid in this situation? You donât? Thatâs all right because there isnât one. Then how should we go about solving this problem? This is where the âhidden triangleâ concept comes into play. The problem here is that we donât know the length of the base of the trapezoid, so weâll need to get a little creative to solve for it. Taking a closer look, we could draw a straight line from the top of the trapezoid to the base to form a triangle as follows:
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Thereâs our hidden triangle. Now we have a rectangle with base 20 and sides 15 attached to a right triangle. If we can figure out the base of the triangle on the left, weâll have all the components needed to figure out the perimeter of the entire shape. Letâs go ahead and apply our Pythagorean Theorem where 17 is the hypotenuse and 15 is one of the sides, and weâll let x be the remaining side:
172 = 152 + x2
289 = 225 + x2
64 = x2
x = 8
Now that we have the base of the triangle, we know that the base of the trapezoid is simply 20 + 8 = 28. Letâs add the other sides together for: 28 + 17 + 15 + 20 = 80, or answer choice D.
You see how hidden triangles have helped us to solve this geometry problem? Look for them the next time you come across an SAT geometry problem.
If you were completely stumped on this problem, you could have also used your SAT test prep strategies to eliminate some incorrect answer choices. We know that the first three sides add up to 52 (17 + 20 + 15). We also know that the base of the trapezoid must be greater than the top or greater than 20. As a result, we know that the perimeter is greater than 72. This allows us to eliminate some answer choices that are too small:
A) 52
B) 72
C) 75
D) 80
E) 87
On top of that, you could probably safely eliminate answer choice C for being too small a value and answer choice E for being too large a value, based on the relative lengths of the rest of the figure. In any case, you gain an edge on this problem and would be in good guessing territory even if unable to reach the full solution. Some clever elimination strategies can be worth a handful of points on the SAT.
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